UPSKILL MATH PLUS

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Step 1: If the given time is \(00\!:\!00\) hours (midnight), then change \(00\!:\!00\) hours as \(12\!:\!00\) a.m. and proceed further. There is no change up to \(12\!:\!59\) p.m.
 
Step 2: If the given time is \(01\!:\!00\) hours to \(12\!:\!59\) hours, then no time change in \(12\)-hour format. Just write the time as it is and mention a.m. at the end of the time up to \(12\)'O clock, mention p.m. at the end of the time after \(12\)'O clock.
 
Step 3: If the given time \(13\!:\!00\) hours to \(23\!:\!59\) hours, then subtract \(12\!:\!00\) hours from the given time and write p.m. at the end of the time.
Example:
1. Convert \(00\!:\!30\) hours to \(12\)-hours format.
 
Solution:
 
By using the above procedure, change \(00\!:\!00\) hours as \(12\!:\!00\) a.m.
 
Therefore, \(00\!:\!30\) hours \(=\) \(12\!:\!30\) a.m.
 
 
2. Write \(06\!:\!20\) hours in ordinary format.
 
Solution:
 
\(06\!:\!20\) hours lies between \(01\!:\!00\) hours to \(12\!:\!59\) hours.
 
By the above procedure, no time change between \(01\!:\!00\) hours to \(12\!:\!59\) hours.
 
\(06\!:\!20\) hours means morning, so mention a.m. at the end of the time.
 
Therefore, \(06\!:\!20\) hours \(=\) \(6\!:\!20\) a.m.
 
 
3. Convert \(22\!:\!10\) hours to \(12\)-hour format.
 
Solution:
 
\(22\!:\!10\) hours lies between \(13\!:\!00\) hours to \(23\!:\!59\) hours.
 
Subtract \(12\!:\!00\) hours from the given time by the above procedure.
 
22:1012:00¯10:10¯
 
\(22\!:\!10\) hours means night, so mention p.m. at the end of the time.
 
Therefore, \(22\!:\!10\) hours \(=\) \(10\!:\!10\) p.m.