PDF chapter test TRY NOW
1. Factorise by using suitable identity.
\(a^2 + 6ab + 9b^2 - c^2 =\)
2. If \(X = a^2 - 1\) and \(Y = 1 - b^2\), then find \(X + Y\) and factorize the same.
Answer:
Factorization of \(X + Y =\)
Answer variants:
\((a + 3b + c)(a + 3b - c)\)
\((a - b)^2\)
\((a + b)(a - b)\)
\((a + 3b - c)(a + 3b - c)\)
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