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Show diagramatically the electron distributions in a sodium atom and a sodium ion and also give their atomic number.
\(_{11}\textrm{Na}^{22}\) = electrons
Hence, electron distribution =
\(Na - 1e^-→Na^+\)
\(Na^+\) = electrons
Hence, electron distribution =
The atomic number of an element is equal to the number of in its atom. Since sodium atom and sodium ion contain the same number of , the atomic number of both is .
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