Solve the real valued function — task. Assessments, Math TN.

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A function

$f: [-5, 9] \rightarrow \mathbb{R}$ is defined as follows:

$f (x) = \{\begin{array}{l} 6 x + 1 \\ 5 x^{2} - 1 \\ 3 x - 4 \end{array} \begin{array}{l} if \\ if \\ if \end{array} \begin{array}{l} - 5 \leq x < 2 \\ 2 \leq x < 6 \\ 6 \leq x \leq 9 \end{array}$ , Then the value of

$\frac{2 f (- 2) - f (6)}{f (4) + f (- 2)}$ is _________

$\frac{8}{14}$
$\frac{- 9}{17}$
$\frac{- 12}{17}$
$\frac{18}{23}$

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3. Solve the real valued function

Exercise condition: