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Math TN
8th Std
Ch-3: Algebra
4.
Factorise by taking out the common factor
Exercise condition:
1
m.
Factorise the expression \(9x^5y^3 + 6x^3y^2 - 18x^2y\) by taking out the common factor:
\(4x^2y(10x^3y^2 + 2xy - 5)\)
\(2x^2y(2x^3y^2 + 3xy + 6)\)
\(3x^2y(3x^3y^2 + 2xy - 6)\)
\(3x^2y(3x^3y^2 - 2xy + 6)\)
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