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In this section, let us look at a few important formulae related to sector and segment of a circle.
Area of a sector
Let us first look at the image given below for a thorough understanding.
Here, OAPB is the sector of a circle with 'r' as the radius. Also, let \angle AOB be \theta.
We are well aware that the area of a circle is \pi r^2.
We also know that any circular region, with O as the centre, is a sector forming the angle 360^\circ.
In other words, the area of a sector forming 360^\circ is \pi r^2.
So, the area of a sector forming 1^\circ = \frac{1}{360} \times \pi r^2 = \frac{\pi r^2}{360}.
Therefore, the area of the sector forming a degree measure of \theta = \frac{\theta}{360} \times \pi r^2.
Thus, \text{The area of a sector} = \frac{\theta}{360} \times \pi r^2, where r is the centre of the circle and \theta is the degree measure of the sector.
The length of an arc of a sector
The length of the whole arc (or the circle) = 2\pi r
Thus, the length of an arc of a sector = \frac{\theta}{360} \times 2\pi r.
Area of the segment APB
Let us look at the image given below for a better understanding.
The area of the segment APB = The area of the sector OAPB - The area of \triangle OAB
= \frac{\theta}{360} \times \pi r^2 - The area of \triangle OAB
Also, \text{The perimeter of the sector} = 2r + \frac{2 \pi r\theta}{360}
Important!
On considering the two figures given below, we come to the conclusions that follow.
1. Area of the major sector OAQB = \pi r^2 – Area of the minor sector OAPB
2. Area of the major segment AQB = \pi r^2 – Area of the minor segment APB