Exemplar exercise problem III — task. Mathematics CBSE, Class 10.

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1. The first four terms of an AP, whose first term is \(–2\) and the common differenc is \(–2\), are

\(– 2, – 4, – 6, – 16\)
\(– 2, – 4, – 6, – 8\)
\(– 2, 4, – 8, 16\)
\(– 2, 0, 2, 4 \)

2. The \(21^{st}\) term of the AP whose first two terms are \(–3\) and \(4\) is

\(-143\)
\(17\)
\(137\)
\(143\)

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