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Find the sum of :
(i) the first \(1000\) positive integers:
(ii) the first \(n\) positive integers:
Sum of the first \(1000\) positive integers \(=\)
Sum of the first \(n\) positive integers \(=\)
Answer variants:
\(\frac{2n(n+1)}{2}\)
\(\frac{n(n+1)}{2}\)
\(\frac{n(n-1)}{2}\)
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