PDF chapter test TRY NOW

i. \(\frac{sin θ – 2 sin^3θ}{2 cos^3θ – cos θ} = tan θ\)
 
ii. \(\frac{1 + tan^2A}{1 + cot^2A}=(\frac{1 – tan A}{1 – cot A})^2 = tan^2A\)
 
Important!
This is a creative exercise. Your teacher will check it manually.