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Express the trigonometric ratios \(sin A, sec A\) and \(tan A\) in terms of \(cot A\).
\(sin A=\)
\(sec A=\)
\(tan A=\)
Answer variants:
\(\frac{1}{\sqrt{1-cot^2A}}\)
\( \frac{\sqrt{cot^2A + 1}}{cot A}\)
\(\frac{1}{cot A}\)
\(\frac{1}{\sqrt{1+cot^2A}}\)
\( \frac{\sqrt{cot^2A - 1}}{cot A}\)
\(\frac{-1}{cot A}\)
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