Show the given trigonometric equation — task. Mathematics CBSE, Class 10.

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Answer variants:

$\frac{\cos α (1 - \sin α)}{1 - \sin^{2} α}$

$\frac{\cos α (1 + \sin α)}{(1 + \sin α) (1 + \sin α)}$

$\frac{\cos α (1 - \sin α)}{(1 + \sin α) (1 - \sin α)}$

$\frac{\cos α (1 + \sin α)}{1 + \sin^{2} α}$

$\frac{1}{\cos α} - \frac{\sin α}{\cos α}$

$\frac{\cos α (1 - \sin α)}{\cos^{2} α}$

$\frac{1 - \sin α}{\cos α}$

Show that

$\frac{\cos α}{1 + \sin α}$

$=$

$\sec α - \tan α$ .

Proof:

LHS

$=$

$\frac{\cos α}{1 + \sin α}$

$=$

$\sec α - \tan α$

$=$ RHS

Did you find an error?

11. Show the given trigonometric equation