Express in terms of the ratio 'sec' — task. Mathematics CBSE, Class 10.

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$\cot θ$ in terms of

$\sec θ$ .

$\frac{1}{\sqrt{\sec θ - 1}}$
$\frac{1}{\sqrt{\sec^2 θ - 1}}$
$\frac{1}{\sqrt{\sec^2 θ + 1}}$
$\frac{1}{\sqrt{\sec θ + 1}}$

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