Express in terms of the ratio 'sec' — task. Mathematics CBSE, Class 10.

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Show \(\cot θ\) in terms of \(\sec θ\).

\(\frac{1}{\sqrt{\sec θ - 1}}\)
\(\frac{1}{\sqrt{\sec^2 θ - 1}}\)
\(\frac{1}{\sqrt{\sec^2 θ + 1}}\)
\(\frac{1}{\sqrt{\sec θ + 1}}\)

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