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The angles of a cyclic quadrilateral ABCD are \angle A = (6x + 10)^{\circ}, \angle B = (5x)^{\circ}, \angle C = (x + y)^{\circ}, \angle D = (3y - 10)^{\circ}.
 
Find x and y, and hence the values of the four angles.
 
Answer:
 
x =
 
y =
 
\angle A = ^{\circ}
 
\angle B = ^{\circ}
 
\angle C = ^{\circ}
 
\angle D = ^{\circ}