Exemplar problems XVI — task. Mathematics CBSE, Class 10.

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Find the zeroes of the polynomial \(x^2 + \frac{1}{6}x - 2\), and verify the relation between the coefficients and the zeroes of the polynomial.

Answer:

The zeroes are

and

Sum of the zeroes \(=\)

Product of the zeroes \(=\)

Answer variants:

\(x = \frac{4}{3}\)

\frac{constant}{coefficient of x^{2}} = 2

\(x = -\frac{2}{3}\)

\frac{constant}{coefficient of x^{2}} = - 2

\frac{- coefficient of x}{coefficient of x^{2}} = \frac{1}{6}

\frac{- coefficient of x}{coefficient of x^{2}} = \frac{- 1}{6}

\(x = \frac{3}{4}\)

\(x = -\frac{3}{2}\)

Did you find an error?

35. Exemplar problems XVI