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Find the zeroes of the polynomial x^2 + \frac{1}{6}x - 2, and verify the relation between the coefficients and the zeroes of the polynomial.
 
Answer:
 
The zeroes are
and
.
 
Sum of the zeroes =
 
Product of the zeroes =
Answer variants:
x = \frac{4}{3}
constantcoefficientofx2=2
x = -\frac{2}{3}
constantcoefficientofx2=2
coefficientofxcoefficientofx2=16
coefficientofxcoefficientofx2=16
x = \frac{3}{4}
x = -\frac{3}{2}