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Find the zeroes of the polynomial 2s^2 - (1 + 2 \sqrt{2})s + \sqrt{2}, and verify the relation between the coefficients and the zeroes of the polynomial.
 
Answer:
 
The zeroes are
and
.
 
Sum of the zeroes =
 
Product of the zeroes =
Answer variants:
constantcoefficientofs2=22
coefficientofscoefficientofs2=1+222
s = \sqrt{2}
s = \frac{1}{2 \sqrt{2}}
s = \frac{1}{2}
coefficientofscoefficientofs2=1+222
s = \frac{3}{\sqrt{2}}
constantcoefficientofs2=22