54. Exemplar Exercise problem XIII

A student says that if you throw a die, it will show up \(1\) or \(not 1\). Therefore, the probability of getting \(1\) and the probability of getting ‘\(not 1\)’ each is equal to \(\frac{1}{2}\) . Is this correct? Give reasons.

 

The given statement is TrueFalse.

 

The probability of getting \(1= \ ) $\frac{i}{i}$

 

The probability of getting \(not 1= \ ) $\frac{i}{i}$