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A box contains 3 blue, 2 white, and 4 red marbles. If a marble is drawn at random from the box, what is the probability that it will be
 
(i) white =
 
(ii) blue =
 
(iii) red =
Answer variants:
\frac{5}{9}
\frac{1}{2}
\frac{2}{9}
\frac{1}{3}
\frac{4}{9}