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Find the discriminant of the equation \(3x^2 – 2x + \frac{1}{3} = 0\) and hence find the nature of its roots. Find them, if they are real.
\(3x^2 – 2x + \frac{1}{3} = 0\) has
The roots of the \(3x^2 – 2x + \frac{1}{3} = 0\) is
Answer variants:
\(\frac{-2}{\sqrt{3}},\frac{2}{\sqrt{3}}\)
\(\frac{2}{\sqrt{3}},\frac{2}{\sqrt{3}}\)
\(\frac{1}{3},\frac{1}{3}\)
\(\frac{-1}{3},\frac{1}{3}\)
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