8. Find the width of the river

A person in the helicopter flying at the height of 670 \(m\) above the river, observes two objects lying opposite to each other on either bank of a river. The angles of depression of the objects are 45\(^{\circ}\) and 30\(^{\circ}\). Then, the width of the river is 1829.441831.441830.441828.44 \(m\).

 

(Note: Substitute \(\sqrt{3} = 1.732\) if necessary.)