Exemplar exercise problems XIV — task. Mathematics CBSE, Class 10.

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The angle of elevation of the top of a vertical tower from a point on the ground is

$60^{\circ}$ . From another point

$10 \ m$ vertically above the first, its angle of elevation is

$45^{\circ}$ . Find the height of the tower.

Answer:

The height of the tower

$=$

$5 \sqrt{3}(\sqrt{3} + 1) \ m$
$5 \sqrt{3}(\sqrt{3} + 1) \ m$
$5 \sqrt{3}(\sqrt{3} - 1) \ m$

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