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The mean of the ungrouped frequency distribution can be determined using the formula:
\overline X = \frac{f_1 x_1 + f_2 x_2 + ... + f_n x_n}{f_1 + f_2 + ... + f_n} = \frac{\sum_{i=1}^{n} f_i x_i}{\sum_{i=1}^{n} f_i}
Example:
The height(in cm) of 20 students in a classroom are:
Height x_i | Number of students f_i |
130 | 1 |
135 | 2 |
140 | 1 |
155 | 2 |
163 | 1 |
165 | 3 |
177 | 2 |
189 | 2 |
196 | 2 |
100 | 4 |
Find the mean height of the 20 students.
Solution:
To find the value of f_ix_i, multiply the value of x and f of each entry.
Consider for the mark 130. That is, 130 \times 1 = 130
Similarly, for the mark 135, we have 135 \times 2 = 270 and so on.
Tabulating these values, we get:
Marks x_i | Frequency f_i | f_ix_i |
130 | 1 | 130 |
135 | 2 | 270 |
140 | 1 | 140 |
155 | 2 | 310 |
163 | 1 | 163 |
165 | 3 | 495 |
177 | 2 | 354 |
189 | 2 | 378 |
196 | 2 | 392 |
100 | 4 | 400 |
Total | \sum f_i = 20 | \sum f_ix_i = 3032 |
Substituting the known values in the above formula, we get:
Mean \overline X = \frac{3032}{20} = 151.6
Therefore, the mean of the given data is 151.6.