Determine the value of the variable — task. Mathematics CBSE, Class 10.

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In a \(\triangle ABC\), \(DE \parallel BC\). If \(AD = 8b - 6\), \(DB = 6b - 2\), \(AE = 8b - 7\) and \(EC = 5b - 3\), then find the value of \(b\).

The value of \(b\) is

$- \frac{1}{2}$
$\frac{1}{2}$
\(2\)
$1$

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