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\(ABCD\) is a trapezium with \(AB||DC\). \(E\) and \(F\) are points on non-parallel sides \(AD\) and \(BC\) respectively such that \(EF\) is parallel to \(AB\). Show that \(\frac{AE}{ED} = \frac{BF}{FC}\).
![YCIND_240214_6037_a_10.png](https://resources.cdn.yaclass.in/6bc80e57-3057-4572-b761-f4719e062e7d/YCIND2402146037a10w200.png)
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