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Now, we shall find the area of a rectangle.
Let us consider a rectangle \(ABCD\) whose length is \(l \ units\) and breadth is \(b \ units\).
Then, the area of the rectangle is given by:
Area of the rectangle \(=\) Product of length and breadth
Area of the rectangle, \(A=length \times breadth\)
\(A=l\times b\) \(sq. units\)
Therefore, the area of the rectangle is \(l\times b\) \(sq. \ units\).
Example:
1. If the length of the rectangle is \(5 \ cm\), and the breadth of the rectangle is \(3 \ cm\), find the area of the rectangle.
Solution:
The length of the rectangle is \(l=5 \ cm\).
The breadth of the rectangle is \(b=3 \ cm\).
Area of the rectangle \(=\) Product of length and breadth
Area, \(A=l \times b \ sq. units\)
Substituting the values in the formula, we have:
\(A=5 \times 3 \ sq. cm\)
\(A=15 \ sq. cm\)
Thus, the area of the rectangle is \(15 \ sq. \ cm\).
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