Area of the rectangle — lesson. Mathematics CBSE, Class 6.

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Now, we shall find the area of a rectangle.

Let us consider a rectangle \(ABCD\) whose length is \(l \ units\) and breadth is \(b \ units\).

Then, the area of the rectangle is given by:

Area of the rectangle \(=\) Product of length and breadth

Area of the rectangle, \(A=length \times breadth\)

\(A=l\times b\) \(sq. units\)

Therefore, the area of the rectangle is \(l\times b\) \(sq. \ units\).

Example:

1. If the length of the rectangle is \(5 \ cm\), and the breadth of the rectangle is \(3 \ cm\), find the area of the rectangle.

Solution:

The length of the rectangle is \(l=5 \ cm\).

The breadth of the rectangle is \(b=3 \ cm\).

Area of the rectangle \(=\) Product of length and breadth

Area, \(A=l \times b \ sq. units\)

Substituting the values in the formula, we have:

\(A=5 \times 3 \ sq. cm\)

\(A=15 \ sq. cm\)

Thus, the area of the rectangle is \(15 \ sq. \ cm\).

Did you find an error?

2. Area of the rectangle