Product of sum and difference (integers) — task. Mathematics CBSE, Class 7.

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Do the multiplication:

({2 e}^{5} - 7 f^{2}) \cdot ({2 e}^{5} + 7 f^{2})

Choose the correct answer:

${4 e}^{10} - {49 f}^{4}$
${2 e}^{10} - {7 f}^{4}$
${4 e}^{10} - {28 e^{5} f^{2} - 49 f}^{4}$
${4 e}^{10} + {28 e^{5} f^{2} + 49 f}^{4}$
${4 e}^{7} - {49 f}^{2}$
${4 e}^{10} - {28 e^{5} f^{2} + 49 f}^{4}$

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