Multiplication of decimals in articles — lesson. Mathematics CBSE, Class 7.

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"The digits are multiplied without using the decimals. Then the decimal point separates as many decimal digits as there are in the multipliers together."

$\begin{array}{l} \underline{\begin{array}{l} 2. 5 \\ \times 1. 6 \end{array}} \\ 150 \\ \underline{25} \\ 4. 00 \end{array}$	First, multiply by articles as integers: $(25 \cdot 16 = 400)$ Then point separated the last $2$ digits ($00$). $2. 5 \times 1. 6 = 4. 00 = 4$
$\begin{array}{l} \underline{\begin{array}{l} 2. 75 \\ \times 0. 16 \end{array}} \\ 1650 \\ 275 \\ \bar{0. 4400} \end{array}$	First, multiply by articles as integers: $(275 \cdot 16 = 4400)$ Then point separated the last $4$ digits ($4400$). $2. 75 \times 0. 16 = 0. 4400 = 0. 44$

0. 01111 \times 55. 5 = 0. 616605

First, multiply the digits as integers.

(1111 \times 555 = 616605)

Then the point separated the last $6$ digits ($616605$).

\begin{array}{l} 0. 01111 \\ \underline{\times 5 5. 5} \\ 5555 \\ 5555 \\ 5555 \\ \bar{0. 616605} \end{array}

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3. Multiplication of decimals in articles

Theory: