Find the unknown value — task. Mathematics CBSE, Class 8.

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Determine the value of \(b\) so that

{(\frac{18}{-6.7})}^{9} \times {(\frac{18}{-6.7})}^{2} = {(\frac{18}{-6.7})}^{9 b - 7}

Answer: \(b\) \(=\)

i i

[Note: Insert \((+)\) or \((-)\) sign in the first answer field.]

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14. Find the unknown value