Find the unknown value — task. Mathematics CBSE, Class 8.

PDF chapter test TRY NOW

Determine the value of \(b\) so that

{(\frac{18}{-6.7})}^{9} \times {(\frac{18}{-6.7})}^{2} = {(\frac{18}{-6.7})}^{9 b - 7}

Answer: \(b\) \(=\)

i i

[Note: Insert \((+)\) or \((-)\) sign in the first answer field.]

Did you find an error?

14. Find the unknown value