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\(ABCD\) is a trapezium whose area is 216 \(cm²\) in which \(AB ∥ CD\), \(DE ⊥ DC\), \(AB =\) 12\(cm\) and \(DC =\) 8\(cm\). Find \(DE\).
Answer: The height of trapezium \(DE\) is \(cm\).
[Note: Round off the answer and insert it as a whole number.]
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