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5. Method to find co-ordinates of a point in a cartesian plane

1. The perpendicular distance of the point

$L$ from the

$y$ - axis measured along the positive direction of the

$y$ -axis is

$LX = 4$ units. The perpendicular distance of the point

$L$ from the

$x$ -axis measured along the positive direction of the

$x$ - axis

$OL = 3$ units.

Point L lies in first quadrant in the above graph. Hence its co-ordinates will be represented as (x, y), where

$x = 3$ and

$y = 4$ the co-ordinate of

$L$ in cartesian plane is

$(3,4)$ .

2. The perpendicular distance of the point

$M$ from the

$y$ - axis measured along the positive direction of the

$y$ -axis is

$MX' = 2$ units. The perpendicular distance of the point

$M$ from the x-axis measured along the negative direction of the

$x$ - axis

$OM = 2$ units.

Point M lies in second quadrant in the above graph. Hence its co-ordinates will be represented as (-x, y), where

$x = 4$ and

$y = 2$ the co-ordinate of M in cartesian plane is

$(-4,2)$ .

3. The perpendicular distance of the point

$N$ from the

$y$ - axis measured along the negative direction of the

$y$ -axis is

$NX' = 3$ units. The perpendicular distance of the point

$N$ from the

$x$ -axis measured along the negative direction of the

$x$ - axis

$OX' = 2$ units.

Point N lies in third quadrant in the above graph. Hence its co-ordinates will be represented as (-x, -y), where

$x = 2$ and

$y = 3$ the co-ordinate of

$L$ in cartesian plane is

$(-2,-3)$ .

4. The perpendicular distance of the point

$Q$ from the

$y$ - axis measured along the negative direction of the y-axis is

$QX' = 3$ units. The perpendicular distance of the point

$Q$ from the

$x$ -axis measured along the positive direction of the

$x$ - axis

$OX = 1$ unit.

Point

$Q$ lies in fourth quadrant in the above graph. Hence its co-ordinates will be represented as (x, -y), where

$x = 1$ and

$y = 3$ the co-ordinate of

$L$ in cartesian plane is

$(1,-3)$ .

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5. Method to find co-ordinates of a point in a cartesian plane

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