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Rationalize the denominators of the following:
(i) \frac{1}{\sqrt{7}}=
(ii) \frac{1}{\sqrt{7}-\sqrt{6}}=
(iii) \frac{1}{\sqrt{5}+\sqrt{2}}=
(iv) \frac{1}{\sqrt{7}-2}=
Answer variants:
\frac{\sqrt{7}+2}{3}
\sqrt{7}+\sqrt{6}
\frac{\sqrt{7}}{7}
\frac{(\sqrt{5}-\sqrt{2})}{(\sqrt{52}+\sqrt{22}})
\frac{1}{7}
\frac{(\sqrt{5}-\sqrt{2})}{3}
\frac{\sqrt{7}-\sqrt{6}}{\sqrt{72}-\sqrt{62}}
\frac{\sqrt{7}-2)}{\sqrt{72}-22}
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