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Subjects
Mathematics CBSE
Class 9
Polynomials
Textbook Questions
26.
Examplar-Exercise Problems I
Exercise condition:
2
m.
1
. Without actually calculating the cubes, find the value of \(48^3 – 30^3 – 18^3\)
\(48^3 – 30^3 – 18^3=\)
\(25920\)
\(51840\)
\(77760\)
\(54260\)
2
. Without finding the cubes, factorise \((x – y)^3 + (y – z)^3 + (z – x)^3\) .
\((x – y)^3 + (y – z)^3 + (z – x)^3=\)
\(2(x-y)(y-z)(z-x)
\(3(x-y)(y-z)(z-x)\)
\(2(x-y-z)(x-z)\)
\(3(x-y-z)\)
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