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Write the following cubes in expanded form:
(i) (\frac{3}{2}x + 1)^3=
(ii) (x − \frac{2}{3}y)^3=
Answer variants:
x^3 –\frac{8}{27} y^3 – 2x^2y + \frac{4}{3} xy^2
\frac{27}{8}x^3 + \frac{27}{4}x^2 + \frac{9}{2}x +1
\frac{27}{8}x^3 + \frac{27}{4}x^2 - \frac{9}{2}x -1
x^3 –\frac{8}{27} y^3 – 2x^2y -\frac{4}{3} xy^2