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Subjects
Mathematics CBSE
Class 9
Polynomials
Textbook Questions
41.
Exemplar Exercise Problems XIV
Exercise condition:
2
m.
Factorise the following :
1
. \(1 – 64a^3 – 12a + 48a^2=\)
2
. \(8p^3+\frac{12}{5}p^2+\frac{6}{25}p+\frac{1}{125}=\)
Answer variants:
\((1-2a)^3\)
\((1+4a)^3\)
\((p-\frac{2}{5})^3\)
\((1+2a)^3\)
\((p+\frac{1}{5})^3\)
\((2p-\frac{1}{5})^3\)
\((1-4a)^3\)
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