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Factorise:
(i) \(64a^3 – 27b^3 – 144a^2b + 108ab^2=\)
(ii) \(7p^3 –\frac{1}{216}− \frac{9}{2}p^2 + \frac{1}{4}p=\)
Answer variants:
\((3p – \frac{1}{6}) (3p – \frac{1}{6}) (3p – \frac{1}{6})\)
\((4a – 3b) (4a – 3b) (4a – 3b)\)
\((4a – 3b) (4a + 3b) (a – 3b)\)
\((3p – \frac{1}{6}) (3p +\frac{1}{6}) (3p + \frac{1}{6})\)
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