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ABC is a triangle right angled at C. A line through the mid-point M of hypotenuse AB and parallel to BC intersects AC at D.
Show that
(i) D is the mid-point of AC
(ii) MD ⊥ AC
(iii) CM = MA = \frac{1}{2}AB
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Important!
The line drawn through the mid-point of one side of a triangle, parallel to another side bisects the third side.