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In right triangle \(ABC\), right angled at \(C, M\) is the mid-point of hypotenuse \(AB\). \(C\) is joined to \(M\) and produced to a point \(D\) such that \(DM = CM\). Point \(D\) is joined to point \(B\).
Show that:
(i) \(∆ AMC ≅ ∆ BMD\)
(ii) \(∠DBC\) is a right angle.
(iii) \(∆ DBC ≅ ∆ ACB\)
(iv) \(CM = \frac{1}{2} AB\)
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