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∆ ABC and ∆ DBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC (see Fig. 7.39).
 
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If AD is extended to intersect BC at P, show that
 
(i) ∆ ABD ≅ ∆ ACD
 
(ii) ∆ ABP≅ ∆ ACP
 
(iii) AP bisects ∠ A as well as ∠ D.
 
(iv) AP is the perpendicular bisector of BC.
 
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