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8. Addition and multiplication on a transpose matrix

Answer variants:

$[\begin{array}{l} -7 & -1 \\ 3 & 2 \end{array}]$

$[\begin{array}{l} 10 & 7 \\ 8 & 3 \end{array}]$

$[\begin{array}{l} -7 & 3 \\ -1 & 2 \end{array}]$

$[\begin{array}{l} 3 & 10 \\ 7 & 5 \end{array}]$

$[\begin{array}{l} -7 & 3 \\ -1 & 2 \end{array}]$

$A = \begin{bmatrix} 3 & 7\\ 10 & 5 \end{bmatrix} , B = \begin{bmatrix} 10 & 8\\ 7& 3 \end{bmatrix}$ then show that

$(A-B)^T = A^T - B^T$

Did you find an error?