Two mark exercise problem VI — task. Mathematics State Board, Class 10.

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Answer variants:

$\frac{α + β}{α β}$

$9 α β - 3 (α + β) + 1$

$\frac{{(α^{2} + β^{2})}^{2} + 2 α β}{3 α β}$

$9 α β + 3 (α + β) - 1$

$\frac{{(α^{2} + β^{2})}^{2} - 2 α β}{3 α β}$

$\frac{α + β}{{(α β)}^{2}}$

Write each of the following expressions in terms of

$\alpha + \beta$ and

$\alpha \beta$ .

(i)

$\frac{\alpha}{3 \beta} + \frac{\beta}{3 \alpha} =$

(ii)

$\frac{1}{\alpha^2 \beta} + \frac{1}{\beta^2 \alpha} =$

(iii)

$(3 \alpha - 1)(3 \beta - 1) =$

Did you find an error?

12. Two mark exercise problem VI