UPSKILL MATH PLUS

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If \(x = \frac{a^2 + 3a - 4}{3a^2 - 3}\)  and \(y = \frac{a^2 + 2a - 8}{2a^2 - 2a - 4}\), find the value of \(x^2 y^{-2}\).
 
Answer:
 
The value of \(x^2 y^{-2}\) is ii.