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If x = \frac{a^2 + 3a - 4}{3a^2 - 3}  and y = \frac{a^2 + 2a - 8}{2a^2 - 2a - 4}, find the value of x^2 y^{-2}.
 
Answer:
 
The value of x^2 y^{-2} is ii.