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Show that the straight lines \(x - 2y + 3 = 0\) and \(6x + 3y + 8 = 0\) are perpendicular.
 
Answer:
 
Slope of \(x - 2y + 3 = 0\) is ii.
 
Slope of \(6x + 3y + 8 = 0\) is .
 
Since \(m_1 \times m_2\) , then the given lines are .