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In the below figure, \(ABC\) is a triangle with \(\angle = 90^\circ\), \(BC = 3 \ cm\) and \(AB = 4 \ cm\). \(D\) is a point on \(AC\) such that \(AD = 1 \ cm\) and \(E\) is the midpoint of \(AB\). Join \(D\) and \(E\) and extend \(DE\) to meet at \(F\). Find \(BF\).
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Answer:
The value of \(BF\) \(=\) \(cm\).
3. Suppose \(AB\), \(AC\) and \(BC\) have lengths \(13\), \(14\) and \(15\) respectively. If \(\frac{AF}{FB} = \frac{2}{5}\) and \(\frac{CE}{EA} = \frac{5}{8}\). Find \(BD\) and \(DC\).
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Answer:
The length of \(BD\) \(=\)
The length of \(DC\) \(=\)