Multiple choice question II — task. Mathematics State Board, Class 10.

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8 (1).png

In the given figure

$\angle BAC = 90^\circ$ and

$AD \perp BC$ then:

$AB \cdot AC = AD^2$
$BD \cdot CD = AD^2$
$BD \cdot CD = BC^2$
$AB \cdot AC = BC^2$

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