Determine the value of the variable — task. Mathematics State Board, Class 10.

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In a \(\triangle ABC\), \(DE \parallel BC\). If \(AD = 6a - 4\), \(DB = 7a - 2\), \(AE = 6a - 6\) and \(EC = 4a - 3\), then find the value of \(a\).

The value of \(a\) is

\(0\)
$\frac{9}{10}$
$\frac{1}{10}$
$\frac{10}{9}$

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