Determine the value of the variable — task. Mathematics State Board, Class 10.

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In a

$\triangle ABC$ ,

$DE \parallel BC$ . If

$AD = 6a - 4$ ,

$DB = 7a - 2$ ,

$AE = 6a - 6$ and

$EC = 4a - 3$ , then find the value of

$a$ .

The value of

$a$ is

$0$
$\frac{9}{10}$
$\frac{1}{10}$
$\frac{10}{9}$

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