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A right angled triangle PQR where \angle Q = 90^\circ is rotated about QR and PQ. If QR = 16 \ cm and PR = 20 \ cm, compare the curved surface areas of the right circular cones so formed by the triangle.
 
Answer:
 
Curved surface area of a cone rotated about QR =  cm^2
 
Curved surface area of a cone rotated about PQ =   cm^2
 
Curved surface area of a cone rotated about PQ is  than the curved surface area of a cone rotated about QR.