UPSKILL MATH PLUS
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Learn moreA right angled triangle \(PQR\) where \(\angle Q = 90^\circ\) is rotated about \(QR\) and \(PQ\). If \(QR = 16 \ cm\) and \(PR = 20 \ cm\), compare the curved surface areas of the right circular cones so formed by the triangle.
Answer:
Curved surface area of a cone rotated about \(QR\) \(=\) \(cm^2\)
Curved surface area of a cone rotated about \(PQ\) \(=\) \(cm^2\)
Curved surface area of a cone rotated about \(PQ\) is than the curved surface area of a cone rotated about \(QR\).
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