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A 22 \(cm\) tall beaker is in the form of a cylinder surmounted on a frustum. The base radius of the cylinder is 2.2 \(cm\) and the height of the frustum is \(6.6\) \(cm\). If the base of the beaker has a radius which is twice that of its rim, then find the volume of the beaker.
Answer:
The volume of the beaker \(=\) \(cm^3\)
[Note: Enter the answer up to two decimal places.]