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Answer variants:
\(\{y | y = (2x + 1)^2, x \in \mathbb{N}\}\)
\(x^4 - 2x\)
\(\{y | y = 2x^2 + 1, x \in \mathbb{N}\}\)
\(\{y | y = 2x + 1, x \in \mathbb{N}\}\)
\(\{y | y = (2x + 1)^3, x \in \mathbb{N}\}\)
\(x^4 - 2x^2 - 1\)
\((x^4 - 2x^2)^2 - 1\)
\(x^4 - 2x^2\)
If \(f(x) = x^2 - 1\). Find:
(i) \(f \circ f\) \(=\)
(ii) \(f \circ f \circ f\) \(=\)
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