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A function \(f : [-7, 6) \rightarrow R\) is defined as:
 
\(f(x) = \begin{cases}
x^2 + 2x + 1 & \text{ if } x= -7 \leq x < -5\\
x + 5 & \text{ if } x= -5 \leq x < 2\\
x - 1 & \text{ if } x= 2 \leq x < 6
\end{cases}\)
 
Then, \(\frac{4f(-3) + 2f(5)}{f(-7) - 3f(0)}\) \(=\) ii
 
[Note: Do not reduce the fraction formed.]