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The event \(A\), \(B\) and \(C\) are mutually inclusive. If \(P(A) = 0.3\), \(P(B) = 0.37\), \(P(C) = 0.29\), \(P(A \cap B) = 0.07\), \(P(B \cap C) = 0.11\), \(P(A \cap C) = 0.13\) and \(P(A \cap B \cap C) = 0.02\), then find the value of \(P(A \cup B \cup C)\).
 
Answer:
 
The value of \(P(A \cup B \cup C)\) \(=\) .