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A boy of height 0.9 \(m\) is walking towards a \(73 \ m\) Qutub minor tower. The angle of elevation from his eyes to the top of the tower increases from 30\(^{\circ}\) to 45\(^{\circ}\) as he walks towards the tower. Find the distance he walked towards the tower. (\(\sqrt{3} = 1.732\))
 
Answer:
 
The distance the boy walked towards the tower is i \(m\).
 
(Note: If it is a whole number, write as it is. If not, round off to \(3\)(max) decimal places.)